How to find nth maximum salary records from a table?

IF  EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[member]') AND type in (N'U'))

DROP TABLE [dbo].[member]

GO

CREATE TABLE [dbo].[member](

[member_no] [int] IDENTITY(1,1) NOT NULL,

[lastname] [varchar](50) NOT NULL,

[firstname] [varchar](50) NULL,

[salary] [decimal](10,2) NULL

)

GO   

ALTER TABLE [member] ADD CONSTRAINT [PK_member_lastname] PRIMARY KEY  -- NONCLUSTERED

(

          [lastname] ASC

         

)WITH (PAD_INDEX  = OFF, IGNORE_DUP_KEY = OFF,  

          ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON, FILLFACTOR = 90) ON [PRIMARY]

GO

SET IDENTITY_INSERT [dbo].[member] ON

INSERT [member] ([member_no], [lastname], [firstname], [Salary])

  VALUES  (1, 'Krishnan', 'Kumar', 10000.00),

 (2, 'Raman', 'Chandrarn', 9000.00),

          (3, 'Durga', 'Prasad',  11000.00),

          (4, 'Saratha', 'Devi',  8000.00),

          (5, 'Shivan', 'Anbu',  9000.00),

          (6, 'Govindaraj', 'Kanniappan', 12000.00),

          (7, 'Parvathi', 'Kumari', 11000.00),

          (8, 'Easwari', 'Sundari', 9500.00)

                  

SET IDENTITY_INSERT [dbo].[member] OFF

-- 5th Maximum salary records

SELECT a.*

FROM member a WITH (NOLOCK) WHERE

5 =(SELECT COUNT(DISTINCT salary)

FROM member b WITH (NOLOCK) WHERE b.salary >= a.salary)

OUTPUT:

member_no	lastname	firstname	salary
2	Raman	Chandrarn	9000.00
5	Shivan	Anbu	9000.00